zhou yang和Claude Opus 5
efcba30a0c
- 规则：铜层 2→4，差分 0.28/0.18，间距 0.15，过孔 0.3/0.2（rules_base） - 几何：98×98 板框 + 4×M3，槽阵居中，L1 12V 大铜 + 指头（pcb_base） - 摆位：五插槽留 L1，其余 133 件翻到 L4；背面镜像规则实测；Hub 放走廊 2、 东移 2.5 mm；扇出圈 / 小件间距 1.5（去耦例外）/ 9 A 过孔阵禁区（place_base） - 叠层按用户决定改为 L1 槽面 / L2 整层 +3V3 / L3 整层 GND / L4 器件面 - 布线：D± 七对按构造布通（USB3 掉头、USB1/2 北去掉头、USB4/5 东绕、 J23 桥），+3V3 / GND / +12V 平面网每脚一孔，0.125 网格 + PathFinder 开关（route_base、remote_route.ps1）；剩 37 个网待手工补 - 铺铜：4 层重写，入口链自南向北切段 + 断面校核（pour_base）； 已下发布线 / 缝合孔 / 铜面轮廓，填铜未成功（待查） - 工具：plot_base / plot_routes / shot_base，board_check 通孔两层都算 Co-Authored-By: Claude Opus 5 <[email protected]> Claude-Session: https://claude.ai/code/session_0168Bu6SEx3cXXCJLkdnE6zB
121 行
5.2 KiB
Python
121 行
5.2 KiB
Python
# -*- coding: utf-8 -*-
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u"""手工补线的净距校验：给一组 (layer, x0,y0,x1,y1, w, net) 段和 (x,y,net) 孔，
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按 `_m6_board_copper.json` + `_blade_pads.json` 算精确净距（判据 0.15）。
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from hand_check import check; check(segs, vias)
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"""
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import io, json, math, os
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HERE = os.path.dirname(os.path.abspath(__file__))
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CLR = 0.15
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VIA_R = 0.3
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PADS = json.load(io.open(os.path.join(HERE, '_blade_pads.json'), encoding='utf-8'))
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CP = json.load(io.open(os.path.join(HERE, '_m6_board_copper.json'), encoding='utf-8'))
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SEGS = [tuple(s) for s in CP['segs']]
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VIAS = [tuple(v) for v in CP['vias']]
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def d_pt_seg(px, py, x0, y0, x1, y1):
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dx, dy = x1 - x0, y1 - y0
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L2 = dx * dx + dy * dy
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t = 0 if L2 == 0 else max(0, min(1, ((px - x0) * dx + (py - y0) * dy) / L2))
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return math.hypot(px - (x0 + dx * t), py - (y0 + dy * t))
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def d_seg_seg(a, b):
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(x0, y0, x1, y1), (u0, v0, u1, v1) = a, b
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# 相交？
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def cross(ax, ay, bx, by): return ax * by - ay * bx
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r = (x1 - x0, y1 - y0); s = (u1 - u0, v1 - v0)
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den = cross(r[0], r[1], s[0], s[1])
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if abs(den) > 1e-12:
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t = cross(u0 - x0, v0 - y0, s[0], s[1]) / den
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u = cross(u0 - x0, v0 - y0, r[0], r[1]) / den
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if 0 <= t <= 1 and 0 <= u <= 1:
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return 0.0
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return min(d_pt_seg(x0, y0, *b), d_pt_seg(x1, y1, *b), d_pt_seg(u0, v0, *a), d_pt_seg(u1, v1, *a))
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def d_seg_rect(seg, rc):
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u"""线段到轴对齐矩形的距离（近似：矩形四边）。"""
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x0, y0, x1, y1 = rc
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if d_pt_seg((x0 + x1) / 2, (y0 + y1) / 2, *seg) < 1e-9:
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return 0.0
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edges = [(x0, y0, x1, y0), (x1, y0, x1, y1), (x1, y1, x0, y1), (x0, y1, x0, y0)]
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d = min(d_seg_seg(seg, e) for e in edges)
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# 线段端点在矩形内？
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for (px, py) in ((seg[0], seg[1]), (seg[2], seg[3])):
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if x0 <= px <= x1 and y0 <= py <= y1:
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return 0.0
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return d
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def pad_rect(p):
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return (p[2] - p[4] / 2, p[3] - p[5] / 2, p[2] + p[4] / 2, p[3] + p[5] / 2)
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def check(new_segs, new_vias, extra_segs=(), extra_vias=(), ignore_segs=()):
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u"""返回违规清单。extra_* 是同批次里别的新线（互相也要查）；ignore_segs 是准备删掉的旧线（按坐标匹配）。"""
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bad = []
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old_segs = [s for s in SEGS if not any(abs(s[1]-g[1])<1e-3 and abs(s[2]-g[2])<1e-3 and abs(s[3]-g[3])<1e-3 and abs(s[4]-g[4])<1e-3 for g in ignore_segs)]
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old_vias = list(VIAS)
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allsegs = old_segs + list(extra_segs)
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allvias = old_vias + list(extra_vias)
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for ns in new_segs:
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l, x0, y0, x1, y1, w, net = ns
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seg = (x0, y0, x1, y1)
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for s in allsegs:
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if s[0] != l or s[6] == net:
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continue
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d = d_seg_seg(seg, s[1:5]) - w / 2 - s[5] / 2
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if d < CLR - 1e-6:
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bad.append(u'段 %s L%d 与线 %s (%.2f,%.2f)-(%.2f,%.2f) 净距 %.3f' % (net, l, s[6], s[1], s[2], s[3], s[4], d))
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for v in allvias:
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if v[2] == net:
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continue
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d = d_pt_seg(v[0], v[1], *seg) - VIA_R - w / 2
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if d < CLR - 1e-6:
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bad.append(u'段 %s L%d 与孔 %s (%.2f,%.2f) 净距 %.3f' % (net, l, v[2], v[0], v[1], d))
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for p in PADS:
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if p[6] != l or p[7] == net:
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continue
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d = d_seg_rect(seg, pad_rect(p)) - w / 2
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if d < CLR - 1e-6:
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bad.append(u'段 %s L%d 与焊盘 %s.%s(%s) 净距 %.3f' % (net, l, p[0], p[1], p[7], d))
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for nv in new_vias:
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vx, vy, net = nv
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for s in allsegs:
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if s[6] == net:
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continue
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d = d_pt_seg(vx, vy, *s[1:5]) - VIA_R - s[5] / 2
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if d < CLR - 1e-6:
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bad.append(u'孔 %s (%.2f,%.2f) 与线 %s L%d (%.2f,%.2f)-(%.2f,%.2f) 净距 %.3f' % (net, vx, vy, s[6], s[0], s[1], s[2], s[3], s[4], d))
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for v in allvias:
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if v[2] == net and abs(v[0]-vx) < 1e-6 and abs(v[1]-vy) < 1e-6:
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continue
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d = math.hypot(v[0] - vx, v[1] - vy) - 2 * VIA_R
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if d < CLR - 1e-6:
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bad.append(u'孔 %s (%.2f,%.2f) 与孔 %s (%.2f,%.2f) 净距 %.3f' % (net, vx, vy, v[2], v[0], v[1], d))
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for p in PADS:
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if p[7] == net:
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continue
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r = pad_rect(p)
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d = math.hypot(max(r[0] - vx, 0, vx - r[2]), max(r[1] - vy, 0, vy - r[3])) - VIA_R
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if d < CLR - 1e-6:
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bad.append(u'孔 %s (%.2f,%.2f) 与焊盘 %s.%s(%s) L%d 净距 %.3f' % (net, vx, vy, p[0], p[1], p[7], p[6], d))
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return bad
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def corridor(l, x0, y0, x1, y1, w, net, margin=1.0):
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u"""列出一条候选线周围 margin 内的一切（帮忙找路）。"""
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seg = (x0, y0, x1, y1)
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out = []
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for s in SEGS:
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if s[0] == l and s[6] != net and d_seg_seg(seg, s[1:5]) < margin:
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out.append(u'线 %s (%.2f,%.2f)-(%.2f,%.2f) w%.2f' % (s[6], s[1], s[2], s[3], s[4], s[5]))
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for v in VIAS:
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if v[2] != net and d_pt_seg(v[0], v[1], *seg) < margin:
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out.append(u'孔 %s (%.2f,%.2f)' % (v[2], v[0], v[1]))
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for p in PADS:
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if p[6] == l and p[7] != net and d_seg_rect(seg, pad_rect(p)) < margin:
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out.append(u'盘 %s.%s(%s) (%.2f,%.2f) %.2fx%.2f' % (p[0], p[1], p[7], p[2], p[3], p[4], p[5]))
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return out
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