64 行
2.5 KiB
Python
64 行
2.5 KiB
Python
#!/usr/bin/env python3
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"""对账 4：封装库完整性。
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三项：
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1. 原理图里每个元件引用的封装，库里都有；
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2. 封装的焊盘号集合 ⊇ 符号的引脚号集合（少一个焊盘 = 网络接不上，PCB 里才会暴露）；
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3. 文件能被 KiCad 解析（交给 kicad-cli 做）。
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"""
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import json, os, re, sys, collections
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sys.path.insert(0, os.path.dirname(os.path.abspath(__file__)))
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from k_netlist import parse_pads
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ROOT = os.path.dirname(os.path.abspath(__file__))
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SRC = os.path.join(ROOT, "eda_src")
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PRETTY = os.path.join(os.path.dirname(ROOT), "kicad", "lib", "PhoneRail.pretty")
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def fp_pads(path):
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s = open(path, encoding="utf-8").read()
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return {m.group(1) for m in re.finditer(r'\(pad "([^"]*)"', s)}
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def main():
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have = {}
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for f in os.listdir(PRETTY):
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if f.endswith(".kicad_mod"):
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have[f[:-10]] = fp_pads(os.path.join(PRETTY, f))
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ok = True
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for board in ("Board1", "Board2"):
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base = parse_pads(os.path.join(SRC, board, "netlist.asc"))
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want = collections.Counter(base["parts"].values())
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missing = sorted(n for n in want if n and n not in have)
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print(f"[{board}] 引用封装 {len(want)} 种", end="")
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if missing:
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print(f" ✘ 库里缺 {len(missing)}: {missing[:6]}"); ok = False
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else:
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print(" ✔ 全部存在")
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# 焊盘号 vs 引脚号
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tree = json.load(open(os.path.join(SRC, "_tree.json"), encoding="utf-8"))
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pages = next(x for x in tree["boards"] if x["board"] == board)["pages"]
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bad = []
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for p in pages:
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g = json.load(open(os.path.join(SRC, board, p["name"] + ".geom.json"), encoding="utf-8"))
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for c in (g["prims"]["Component"] or []):
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if c["ComponentType"] != "part":
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continue
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fp = (c.get("Footprint") or {}).get("name")
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if fp not in have:
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continue
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pins = {str(q["PinNumber"]) for q in (c.get("__pins") or [])}
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miss = pins - have[fp]
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if miss:
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bad.append((c["Designator"], fp, sorted(miss)[:4]))
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if bad:
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print(f" ✘ 引脚号在封装里找不到对应焊盘 {len(bad)}: {bad[:4]}"); ok = False
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else:
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print(" ✔ 焊盘号覆盖全部引脚号")
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print("\n" + ("封装库检查通过 ✔" if ok else "封装库有问题 ✘"))
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sys.exit(0 if ok else 1)
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if __name__ == "__main__":
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main()
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