R2：底板 / 刀片布局布线脚本、快照、截图与规划文档更新（含外壳、打印件、布线归档）

Co-Authored-By: Claude Opus 5.5 <[email protected]>

.claude/r2/shell/check_coaxial.py

@@ -0,0 +1,107 @@
+# -*- coding: utf-8 -*-
+u"""只读：端板 R2.1 螺母孔 ↔ 相邻板 R1.7 过孔 的同轴配对（按「横向对齐 + 轴向最近」配）。
+
+swap_endplate_v12.py 的第一版只比横向偏差，南北板过孔 (x,z) 完全相同，
+北侧 4 孔全被配到了南板 —— 等于没验北板。这里修正为轴向最近。
+"""
+import io
+import sys
+
+sys.stdout = io.TextIOWrapper(sys.stdout.buffer, encoding='utf-8', write_through=True)
+import win32com.client as wc
+
+
+def prop(o, n):
+    v = getattr(o, n)
+    return v() if type(v).__name__ in ('method', 'function', 'builtin_function_or_method') else v
+
+
+def D(x):
+    return x if hasattr(x, '_oleobj_') else wc.Dispatch(x)
+
+
+app = wc.GetActiveObject('SldWorks.Application')
+doc = app.ActiveDoc
+print(u'总装', prop(doc, 'GetTitle'))
+
+
+def world_holes(comp, radius):
+    xf = list(prop(comp, 'Transform2').ArrayData)
+    R, T = xf[0:9], [xf[9] * 1000, xf[10] * 1000, xf[11] * 1000]
+    out = []
+    for bd in comp.GetBodies2(0) or []:
+        for f in prop(D(bd), 'GetFaces'):
+            s = prop(D(f), 'GetSurface')
+            if not prop(s, 'IsCylinder'):
+                continue
+            cp = list(prop(s, 'CylinderParams'))
+            if abs(cp[6] * 1000 - radius) > 0.01:
+                continue
+            p = [cp[0] * 1000, cp[1] * 1000, cp[2] * 1000]
+            a = cp[3:6]
+            gp = [p[0] * R[0] + p[1] * R[3] + p[2] * R[6] + T[0],
+                  p[0] * R[1] + p[1] * R[4] + p[2] * R[7] + T[1],
+                  p[0] * R[2] + p[1] * R[5] + p[2] * R[8] + T[2]]
+            ga = [a[0] * R[0] + a[1] * R[3] + a[2] * R[6],
+                  a[0] * R[1] + a[1] * R[4] + a[2] * R[7],
+                  a[0] * R[2] + a[1] * R[5] + a[2] * R[8]]
+            # 圆柱面的轴点在 CylinderParams 里是任意一点 ⇒ 取面 box 的轴向中点更有意义
+            fb = [v * 1000 for v in prop(D(f), 'GetBox')]
+            out.append((ga, gp, fb))
+    return out
+
+
+nuts, thru = [], []
+for c in doc.GetComponents(True):
+    nm = prop(c, 'Name2').upper()
+    if 'ENDPLATE' in nm:
+        nuts += [(nm, *h) for h in world_holes(c, 2.1)]
+    elif any(k in nm for k in ('SOUTHPANEL', 'NORTHPANEL', 'TOPPANEL')):
+        thru += [(nm, *h) for h in world_holes(c, 1.7)]
+
+# 过孔的装配 box 需要单独取（组件级 box 在世界坐标）：用轴点 + 板位置判断即可
+comp_box = {prop(c, 'Name2').upper(): [v * 1000 for v in c.GetBox(False, False)]
+            for c in doc.GetComponents(True)}
+
+ok_n = 0
+for nm, ga, gp, _ in nuts:
+    ai = max(range(3), key=lambda i: abs(ga[i]))
+    o = [i for i in range(3) if i != ai]
+    best = None
+    for tn, ta, tp, _ in thru:
+        if max(range(3), key=lambda i: abs(ta[i])) != ai:
+            continue
+        lat = max(abs(gp[i] - tp[i]) for i in range(3) if i != ai)
+        if lat >= 0.05:
+            continue
+        cb = comp_box[tn]
+        axial = abs((cb[ai] + cb[ai + 3]) / 2.0 - gp[ai])     # 板中面 ↔ 螺母孔轴点
+        if best is None or axial < best[0]:
+            best = (axial, tn, lat)
+    # 螺母孔在角柱里、紧贴该板 ⇒ 轴向距离应在 板厚 + 柱宽 量级（≤ 15）
+    ok = best is not None and best[0] <= 15.0
+    ok_n += ok
+    print(u'  %-15s 轴%s (%s=%7.2f, %s=%6.2f) ↔ %-15s 横偏 %.3f 轴距 %5.2f %s'
+          % (nm[:15], 'xyz'[ai], 'xyz'[o[0]], gp[o[0]], 'xyz'[o[1]], gp[o[1]],
+             best[1][:15] if best else '-', best[2] if best else -1,
+             best[0] if best else -1, u'✅' if ok else u'⛔'))
+print(u'配到相邻板 %d / %d' % (ok_n, len(nuts)))
+
+# ── 端板 L 脚锁孔（R1.7、轴沿 z）↔ 托盘锁孔（R1.7、轴沿 z）────────────────
+feet, tray = [], []
+for c in doc.GetComponents(True):
+    nm = prop(c, 'Name2').upper()
+    hs = world_holes(c, 1.7)
+    zs = [(nm, ga, gp) for ga, gp, _ in hs if abs(ga[2]) > 0.99]
+    if 'ENDPLATE' in nm:
+        feet += zs          # 风扇螺孔是轴沿 x 的，已被过滤掉
+    elif 'TRAY' in nm:
+        tray += zs
+fok = 0
+for nm, ga, gp in feet:
+    best = min((max(abs(gp[0] - tp[0]), abs(gp[1] - tp[1])), tn) for tn, _, tp in tray) if tray else None
+    ok = best is not None and best[0] < 0.05
+    fok += ok
+    print(u'  %-15s 脚锁孔 (x=%7.2f, y=%6.2f) ↔ %-10s 横偏 %.3f %s'
+          % (nm[:15], gp[0], gp[1], best[1][:10] if best else '-', best[0] if best else -1, u'✅' if ok else u'⛔'))
+print(u'脚锁孔对上托盘 %d / %d（期望 4）' % (fok, len(feet)))