skill：solidworks-assembly 实测笔记与脚本、easyeda-sch-geometry 补充
Co-Authored-By: Claude Opus 5.5 <[email protected]>
这个提交包含在：
zhou yang
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# -*- coding: utf-8 -*-
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u"""量 PCIE 插槽**顶面开口**的真实长宽 —— 判断刀片舌头 36.0 插不插得进。
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为什么不能用碰撞法：插槽模型把簧片触点建成了**刚性**的，两排触点自由间隙只有
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1.22 mm，而 STEP 里刀片板厚 1.67 ⇒ 干涉检查在任何位置都报"插不进"，
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与舌头宽度无关。所以必须**直接量开口**。
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两条互相独立的口径（两个都给，不一致就说明哪条的假设不成立）：
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A. 顶面那个平面的**内环**（inner loop）包围盒 = 开口轮廓
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B. 落在卡槽通道里（|y − 通道中心| 小）的所有面的 x 并集 = 通道长度
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⛔ 全程不碰 IInterferenceDetectionMgr（NOTES §24）。
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"""
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import io, re, subprocess, sys, time
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sys.stdout = io.TextIOWrapper(sys.stdout.buffer, encoding='utf-8')
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import pythoncom
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import win32com.client as wc
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BASE_STEP = r'D:\DCDC\新建文件夹\3D_BASE-PCB_2026-09-12.step'
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def prop(o, name):
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u"""0 参成员：多数是属性，但 GetFaces / GetLoops 这类是方法（NOTES §25）。
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⛔ 不能用 callable() 判断（COM 对象一律 callable，§2），只认 python 方法类型。"""
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v = getattr(o, name)
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if type(v).__name__ in ('method', 'function', 'builtin_function_or_method'):
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return v()
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return v
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def D(x):
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return x if hasattr(x, '_oleobj_') else wc.Dispatch(x)
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def sw_pids():
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out = subprocess.run(['tasklist', '/FI', 'IMAGENAME eq SLDWORKS.EXE', '/FO', 'CSV', '/NH'],
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capture_output=True, text=True, encoding='gbk', errors='ignore').stdout
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return sorted(re.findall(r'"SLDWORKS\.exe","(\d+)"', out, re.I))
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app = None
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try:
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app = wc.GetActiveObject('SldWorks.Application')
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print(u'✅ 复用现有实例（文档数 %s）' % app.GetDocumentCount)
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except Exception as e:
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print(u'✗ 连不上 (%s) → 自愈' % str(e)[:50])
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if sw_pids():
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subprocess.run(['taskkill', '/F', '/IM', 'SLDWORKS.exe'], capture_output=True)
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time.sleep(4)
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for k in range(20):
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try:
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app = wc.Dispatch('SldWorks.Application'); app.Visible = True
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_ = app.RevisionNumber; break
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except Exception:
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if k == 19: raise
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time.sleep(5)
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if app.GetDocumentCount == 0:
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print(u'导入底板 STEP…')
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data = app.GetImportFileData(BASE_STEP)
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err = wc.VARIANT(pythoncom.VT_BYREF | pythoncom.VT_I4, 0)
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t0 = time.time(); app.LoadFile4(BASE_STEP, 'r', data, err)
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print(u' err=%s %.1fs' % (err.value, time.time() - t0))
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part = None
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for d in app.GetDocuments:
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try:
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if d.GetType == 1 and 'PCIE' in d.GetTitle.upper() and '64P11L' in d.GetTitle.upper():
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part = d; break
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except Exception:
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pass
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if part is None:
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print(u'⛔ 没找到插槽零件'); sys.exit(1)
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print(u'零件: %s' % part.GetTitle)
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# 取面数最多的那个实体 = 塑料壳
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shell, nmax = None, -1
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for bd in part.GetBodies2(0, True):
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b = D(bd)
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try:
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n = len(prop(b, 'GetFaces'))
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except Exception:
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continue
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if n > nmax:
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shell, nmax = b, n
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print(u'塑料壳实体：%d 个面' % nmax)
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faces = prop(shell, 'GetFaces')
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# ── 找顶面（法线 +Z、z 最高的平面）───────────────────────────────────
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top, topz = None, -1e9
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info = []
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for f in faces:
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fc = D(f)
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try:
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s = prop(fc, 'GetSurface')
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if not prop(s, 'IsPlane'):
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continue
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nz = list(prop(s, 'PlaneParams'))[2]
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fb = [v * 1000 for v in prop(fc, 'GetBox')]
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info.append((fc, nz, fb))
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if nz > 0.99 and fb[5] > topz:
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top, topz = fc, fb[5]
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except Exception:
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continue
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print(u'顶面 z = %.3f' % topz)
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# ── 口径 A：顶面的内环 ───────────────────────────────────────────────
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print(u'\n=== 口径 A：顶面的环（内环 = 开口）===')
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try:
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loops = prop(top, 'GetLoops')
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print(u' 共 %d 个环' % len(loops))
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for li, lp in enumerate(loops):
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L = D(lp)
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try:
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outer = prop(L, 'IsOuter')
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except Exception:
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outer = '?'
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xs, ys = [], []
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try:
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for e in prop(L, 'GetEdges'):
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E = D(e)
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try:
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cp = list(prop(E, 'GetCurveParams2'))
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pts = [(cp[0], cp[1], cp[2]), (cp[3], cp[4], cp[5])]
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except Exception:
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pts = []
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for p in pts:
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xs.append(p[0] * 1000); ys.append(p[1] * 1000)
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except Exception as ex:
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print(u' 环%d 取边失败 %s' % (li, str(ex)[:50])); continue
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if xs:
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print(u' 环%-2d 外环=%-5s x %8.3f~%8.3f (%6.3f) y %7.3f~%7.3f (%5.3f)'
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% (li, outer, min(xs), max(xs), max(xs) - min(xs),
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min(ys), max(ys), max(ys) - min(ys)))
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except Exception as e:
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print(u' ⛔ 取环失败: %s' % str(e)[:90])
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# ── 口径 B：卡槽通道里所有面的 x 并集 ────────────────────────────────
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print(u'\n=== 口径 B：卡槽通道内各面的 x 并集 ===')
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YC = 0.74 # 通道中心线（由两排触点 -0.56 / +2.04 推出）
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for halfw in (0.7, 0.9, 1.2):
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xs = []
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for fc, nz, fb in info:
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ymid = (fb[1] + fb[4]) / 2.0
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if abs(ymid - YC) < halfw and fb[5] > 1.5 and fb[2] < topz + 0.01:
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xs.append(fb[0]); xs.append(fb[3])
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if xs:
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print(u' |y−%.2f|<%.1f ⇒ x %8.3f ~ %8.3f，通道长 **%.2f mm**'
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% (YC, halfw, min(xs), max(xs), max(xs) - min(xs)))
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print(u'\n对照：刀片舌头 36.00 mm（TONGUE_X0/X1 = 27.0/63.0，板局部）')
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print(u' 塑料体全长 41.00 mm，顶面平面跨度 39.00 mm')
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在新工单中引用
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